# 1. The following sets of data shows the mean marks of 43 interviewees from a certain job interview that was conducted by a HR Consulting Firm in Mombasa: 23, 45, 79, 15, 47, 64, 33, 26, 34, 46, 31, 29, 49, 25, 45, 43, 39, 45, 22, 26, 28, 36, 42 Using the concept of sampling distribution, what sample size will give at least a 0.95 probability that the sample mean is greater than $8 of the population mean?

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2 polynomial long division

dividing : x4+5x3-4x2-8x+6

("dividend")

by : x-1 ("divisor")

dividend x4 + 5x3 - 4x2 - 8x + 6

- divisor * x3 x4 - x3

remainder 6x3 - 4x2 - 8x + 6

- divisor * 6x2 6x3 - 6x2

remainder 2x2 - 8x + 6

- divisor * 2x1 2x2 - 2x

remainder - 6x + 6

- divisor * -6x0 - 6x + 6

remainder 0

quotient : x3+6x2+2x-6 remainder: 0

step-by-step explanation:

answer: 486in^2

step-by-step explanation: